(B) The given quadratic equation is $x^{2}-10x+(2k-1)=0$.Comparing this with the standard form $ax^{2}+bx+c=0$,we get $a=1$,$b=-10$,and $c=2k-1$.The d

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(B) The given quadratic equation is $x^{2}-10x+(2k-1)=0$.Comparing this with the standard form $ax^{2}+bx+c=0$,we get $a=1$,$b=-10$,and $c=2k-1$.The discriminant $D$ is given by the formula $D=b^{2}-4ac$.Given $D=40$,we substitute the values:$40 = (-10)^{2} - 4(1)(2k-1)$$40 = 100 - 4(2k-1)$$40 = 100 - 8k + 4$$40 = 104 - 8k$$8k = 104 - 40$$8k = 64$$k = 8$.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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If the discriminant of $x^{2}-10x+(2k-1)=0$ is $40$,then $k=$...............

A
$79$
B
$8$
C
$13$
D
$15$

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Mix Examples - Quadratic Equations

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If the discriminant of $x^{2}-10x+(2k-1)=0$ is $40$,then $k=$...............

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The value of the discriminant of the quadratic equation $5x^{2} + x + 2 = 0$ is ..... .

The golden number $\frac{1+\sqrt{5}}{2}$ is one of the solutions of ...... .

Solve the following equation using the method of factorization: $6(2x+1)^2 - (2x+1) - 5 = 0$

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2}+5x+5=0$

What is the value of $k$ if one of the roots of the quadratic equation $x^{2} + 6x + k = 0$ is $-4$?

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